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-245=-45u^2
We move all terms to the left:
-245-(-45u^2)=0
We get rid of parentheses
45u^2-245=0
a = 45; b = 0; c = -245;
Δ = b2-4ac
Δ = 02-4·45·(-245)
Δ = 44100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{44100}=210$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-210}{2*45}=\frac{-210}{90} =-2+1/3 $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+210}{2*45}=\frac{210}{90} =2+1/3 $
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